+2407 z^7 + 8z^4 - 2iz^3 - 16i = 0
z^4(z^3 + 8) - 2i(z^3 + 8) = 0
(z^4 - 2i)(z^3 + 8) = 0
So... (z^4 - 2i) = 0 or (z^3 + 8) = 0
Remember to thank the past answerers to your questions. :))
=^._.^=
+24 Wait im kind of confused on how you went from this z^4(z^3 + 8) - 2i(z^3 + 8) = 0 to this (z^4 - 2i)(z^3 + 8) = 0. The answer is prob correct tho.
+118667 Thanks catmg 
Hi Tr1
Think about this
3x + 5x = 8x because you started with 3x and you added another 5x. so you have (3+5)x
ctmeg had
z^4(z^3 + 8) - 2i(z^3 + 8) = 0
Here you have z^4 lots of (x^3+8) and from that you are taking away 2i lots of (z^3+8)
so you end up with
\((z^4-2i) \;\;lots\;\; of \;\;(z^3+8) = (z^4-2i) ( z^3+8) \)
Think about it.
