Four standard fair -sided dice are rolled. What is the probability that the sum of the numbers rolled is even?
50% chance of getting an even on one die
4 even 1/(2^4)
2even [1/(2^4) ]* 4!/(2!2!)
0even 1/(2^4)
Now add them together. That's what I think.
The product is different (i think) because to get an even product, you need even x even or even x odd; odd only happens with odd x odd.