There are four different fourth roots of 16. That is, there are four complex numbers that can be x in the equation below:
x^4=16
What are the four complex numbers?
+6248 \(16 = 16 e^{i 2\pi k},~k \in \mathbb{Z}\\ \sqrt[4]{16} = \sqrt[4]{16}e^{i \frac{2\pi k }{4}},~k = 0, 1, 2, 3 = \\ 2e^{0},~2e^{i\pi/2},~2e^{i\pi},~2e^{i3\pi/2} = \\ 2, 2i, -2, -2i\)
+2862 I haven't learned this yet, so just curious, how would 2 be considered to be a complex number?
