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Jeraine spent 1/10 of her money to buy 8 erasers and 3 pencils. 
The cost of 1 pencil was twice the cost of 1 eraser.

She bought more erasers with 1/3 of her remaining money.

(a) How many erasers can Jeraine buy with 1/10 of her money?

(b) Find the number of erasers Jeraine bought altogether.

 Aug 25, 2021
 #1
avatar+47 
+1

Hi Guest! Think of it as an algebra sum but instead of x and y we have pencils (p) and erasers (e) and p=2e (pencils cost double the amount of an eraser) so 

1/10 of her money=8e+3p since p=2e

=8e+3(2e)

=8e+6e

=14e 

So the answer to (a) is 14

 

 

SCZ

 Aug 25, 2021
edited by SmartCookiezZ  Aug 25, 2021
 #4
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CORRECT!!!

Guest Aug 25, 2021
 #2
avatar+47 
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Hey Guest!

This my attempt at (b) ok so in a we found that 1/10 of her money could buy 14 erasers, its says with 1/3 of her remaining money she bought more erasers after spending 1/10 she had 9/10 left. 1/3 of 9/10 is 3/10 presuming she spent that 1/3 on just erasers with no change then

1/10=14

3/10=14×3

=42

 

I hope I helped

 

SCZ

 Aug 25, 2021
 #3
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-1

WRONG!!!

Guest Aug 25, 2021
 #5
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Ok my answer for b was wrong and I have to admit it was a very silly mistake on my part. I answered 42 which would have been correct if they asked how many she bought with 1/3 of her remaining money but I forgot to add the amount she bought at the start if I had I would have gotten 50, Sorry again for the incorrect answer and I hope this is the correct answer.

 

SCZ

 Aug 25, 2021
 #7
avatar+86 
0

Found it the same way SmartCookiezZ found it

 Aug 26, 2021

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