4 12-sided dice are rolled. What is the probability that the number of dice showing a two digit number is equal to the number of dice showing a one digit number? Express your answer as a common fraction. (Assume that the numbers on the 12 sides are the numbers from 1 to 12 expressed in decimal.)

 Apr 17, 2018

I'll take a stab at this one.....if the number of dice showing a two-digit number  = the number of dice showing a one-digit number, then  2 must show a two-digit number and 2  must show a one-digit number


There are 3 two-digit numbers and 9 one-digit numbers on each die


So....the probabiity is


C(4,2) (3/12)^2 (9/12)^2    =  


C(4,2) (1/4)^2 (3/4)^2  =




cool cool cool 

 Apr 17, 2018

10 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.