Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
778
1
avatar+31 

At time t=0,$ a ball is thrown downward at 24 feet per second from a height of 160 feet above the ground. The equation h = -16t^2 - 24t +160$ describes the height (in feet) of the ball. In how many seconds will the ball hit the ground? Express your answer as a decimal.

 May 23, 2019

Best Answer 

 #1
avatar+6251 
+2

h(t)=16t224t+160=8(2t23t+20) h(t)=0(2t2+3t20)=0 t3±9+1604=3±134=52,4 Clearly 52s=2.5s is the solution we want

.
 May 23, 2019
 #1
avatar+6251 
+2
Best Answer

h(t)=16t224t+160=8(2t23t+20) h(t)=0(2t2+3t20)=0 t3±9+1604=3±134=52,4 Clearly 52s=2.5s is the solution we want

Rom May 23, 2019

4 Online Users

avatar
avatar
avatar