There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form

Guest Jan 13, 2019

#1**+1 **

there are 10c2 or 45 games total

and there are 5c2 or 10 games where it is boy-v-boy

so it is 10/45 or 2/9

HOPE THIS HELPED!

asdf335 Jan 13, 2019

#2**+2 **

We found from Chris' previous answer that girl vs girl (or boy vs boy) is 10 games

Total games would be 10C2 = 45

10/45 = 2/9

ElectricPavlov Jan 13, 2019

#3**+2 **

As in your other question....the girls play 10 games against each other

And the boys play the same number

Each boy (or girl) plays the opposite counterpart 5 * 5 = 25 times

So......the number of total games = 10 + 10 + 25 = 45

So....the fractional number of boy-boy games is 10 / 45 = 2 / 9

CPhill Jan 13, 2019