There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.
What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form
there are 10c2 or 45 games total
and there are 5c2 or 10 games where it is boy-v-boy
so it is 10/45 or 2/9
HOPE THIS HELPED!
We found from Chris' previous answer that girl vs girl (or boy vs boy) is 10 games
Total games would be 10C2 = 45
10/45 = 2/9
As in your other question....the girls play 10 games against each other
And the boys play the same number
Each boy (or girl) plays the opposite counterpart 5 * 5 = 25 times
So......the number of total games = 10 + 10 + 25 = 45
So....the fractional number of boy-boy games is 10 / 45 = 2 / 9
i am going to post my own question; i can probably solve it on my own but i will post it anyway