Find all real values of x such that
(x^2 + 2x + 5 - x - 4)(3x^2 - x - 4 + 2x + 8) >= 0
+1632 When graphed on desmos, it turns out any real value of x works.
Well why? Because all the values of x after applying zero product property are imaginary, meaning the parabola is above the x-axis, hence the y values are always positive. Positive x Positive = Positive, so any real value of x will obtain >=0
