We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
177
2
avatar

At a party there are only single women and married men with their wives. The probability that a randomly selected woman is single is 2/5. What fraction of the people in the room are married men?

 Jan 22, 2019
 #2
avatar+28159 
+3

Let number of single women be ws and number of married women be wm (Hence number of men = wm)

 

We are told:  ws/wm = 2/5

 

fraction of men:   fm = wm/(ws+2wm) 

 

Divide numerator and denominator by wm:   fm = 1/(ws/wm + 2), hence fm = 1/(2/5 + 2)  or fm = 5/12

 Jan 22, 2019

21 Online Users

avatar