Marie needs to mix 40 saline solution with a 60 saline solution to create 200 millimeters of a 54% solution. how many mm of each solution must Marie use?
x = 40 % solution amount of saline .4x
200-x = 60% solution amount of saline .6 (200-x) summed they equal the final product .54 (200)
.4x + .6(200-x) = .54(200) solve for x this is the ml of 40% then 60% = 200-x ml