If a 260N rock is lifted with a lever having an IMA of 4.0, how much force must be exerted under ideal conditions? Over what distance would this force have to be exerted if the rock is to be lifted 0.50m?
\(F= \dfrac{260N}{4} = 65N\\ d = 4(0.5m)= 2m\\ \text{Note that the work done }F\cdot d \text{ is constant}\)
how did you figure this out?
+1438 
