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If a 260N rock is lifted with a lever having an IMA of 4.0, how much force must be exerted under ideal conditions? Over what distance would this force have to be exerted if the rock is to be lifted 0.50m? 

 Mar 14, 2019
 #1
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\(F= \dfrac{260N}{4} = 65N\\ d = 4(0.5m)= 2m\\ \text{Note that the work done }F\cdot d \text{ is constant}\)

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 Mar 14, 2019
 #2
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how did you figure this out?

SmartMathMan  Mar 15, 2019

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