We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
171
4
avatar+1112 

What is the IMA of a 1.5m broom if it is held at the very top and the input force is applied 0.60m below the end of the handle? 

 Mar 15, 2019
edited by SmartMathMan  Mar 15, 2019
edited by SmartMathMan  Mar 15, 2019
edited by SmartMathMan  Mar 15, 2019
 #1
avatar+105468 
+1

If you called it 'Physics - Forces' or some other descriptive name you might attract better help.

 Mar 15, 2019
 #2
avatar+1112 
0

thx.

SmartMathMan  Mar 15, 2019
 #3
avatar+1112 
0

Do you know the formula for me to solve this? I can't figure it out.

SmartMathMan  Mar 15, 2019
 #4
avatar+1791 
+3

This is very simple! The reasons you do not know the formula is because you are not paying attention in class and you are not reading your assigned texts.  Translation: you are fucking around instead of studying.

 

This question describes a class-three (3) fulcrum. The fulcrum is to one side (the broom top), the load is on the other side, and the effort is in the middle. A class-three (3) lever always has an Ideal Mechanical Advantage of less than 1. For a broom, the mechanical disadvantage translates to a distance advantage. That is, a short motion near the fulcrum results in a longer motion further away.  

 

The formula is the same for all three classes of levers.

  \(\bf IMA = \dfrac{d_i}{d_o}\) where i and o are the input and output distances from the fulcrum. 

 

 

GA

 Mar 17, 2019

28 Online Users

avatar