I need help with polygons
Let B, A, and D be three consecutive vertices of a regular -gon. A regular heptagon is constructed on AB with a vertex C next to A Find angle BCD in degrees.
Angle BCD is equal to 65.5°.
What is the formula for the interior angle of a regular polygon?
The interior angle of a polygon = sum of interior angles and the number of sides is the formula for determining the amount of an interior angle.
It is given that B, A, and D are three consecutive vertices of a regular 8-gon.
The interior angle of a regular 8-gon (Octagon) is 135°.
It is given that C is a vertex of a regular heptagon(7-gon) whose one side is AB.
C, B, and D are at equal distances from A.
So A is the center and C, B, and D are points on the circle.
BD is the cord that is making an angle of 135° at A(center).
At the circumference, the cord makes half the angle.
So angle BCD is equal to 135/2 = 65.5°.