What is the average of all the integer values of M such that {M}/{56} is strictly between {3}/{7} and {1}/{4}?

Guest May 3, 2019

#1**+2 **

\(\frac{1}{4}<\frac{M}{56}<\frac{3}{7}\)

To do this, I would multiply everything by 56.

\((56)(\frac{1}{4})<(56)(\frac{M}{56})<(56)(\frac{3}{7})\)

56*1/4=14

56*M/56=M

56*3/7=24

\(14

All integer values of M between 14 and 24 are \(15, 16, 17, 18, 19, 20, 21, 22, 23\).

Add them all together.

\(15+16+17+18+19+20+21+22+23 = 171\)

Divide the whole thing by 9, since that is the number of terms present.

\(\frac{171}{9} = 19\)

The average is 19.

AdamTaurus May 3, 2019

#1**+2 **

Best Answer

\(\frac{1}{4}<\frac{M}{56}<\frac{3}{7}\)

To do this, I would multiply everything by 56.

\((56)(\frac{1}{4})<(56)(\frac{M}{56})<(56)(\frac{3}{7})\)

56*1/4=14

56*M/56=M

56*3/7=24

\(14

All integer values of M between 14 and 24 are \(15, 16, 17, 18, 19, 20, 21, 22, 23\).

Add them all together.

\(15+16+17+18+19+20+21+22+23 = 171\)

Divide the whole thing by 9, since that is the number of terms present.

\(\frac{171}{9} = 19\)

The average is 19.

AdamTaurus May 3, 2019