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How would i write this in standard form???

 Jun 3, 2019
 #1
avatar+8577 
+4

We're given a point and a slope so we can easily write the equation of the line in point-slope form.

The equation of the line in point-slope form is....

 

y - -4  =  -\(\frac38\)(x - 5)

 

Now we just need to get this equation into standard form.

The standard form of a line is  Ax + By = C  where A is a positive integer, and B and C are integers.

 

y - -4  =  -\(\frac38\)(x - 5)

 

y + 4  =  -\(\frac38\)(x - 5)

                                     Multiply both sides of the equation by  8 .

8(y + 4)  =  -3(x - 5)

                                     Distribute the  8  and the  -3

8y + 32  =  -3x + 15

                                     Add  3x  to both sides of the equation.

3x + 8y + 32  =  15

                                     Subtract  32  from both sides.

3x + 8y  =  -17

 

Now the equation is in standard form. Here's a graph: https://www.desmos.com/calculator/momem4spgv

 Jun 3, 2019

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