+0

# Help plz

+1
278
1
+46

How would i write this in standard form???

Jun 3, 2019

#1
+8961
+4

We're given a point and a slope so we can easily write the equation of the line in point-slope form.

The equation of the line in point-slope form is....

y - -4  =  -$$\frac38$$(x - 5)

Now we just need to get this equation into standard form.

The standard form of a line is  Ax + By = C  where A is a positive integer, and B and C are integers.

y - -4  =  -$$\frac38$$(x - 5)

y + 4  =  -$$\frac38$$(x - 5)

Multiply both sides of the equation by  8 .

8(y + 4)  =  -3(x - 5)

Distribute the  8  and the  -3

8y + 32  =  -3x + 15

Add  3x  to both sides of the equation.

3x + 8y + 32  =  15

Subtract  32  from both sides.

3x + 8y  =  -17

Now the equation is in standard form. Here's a graph: https://www.desmos.com/calculator/momem4spgv

Jun 3, 2019