+0  
 
0
234
1
avatar+567 

Suppose ten distinct, positive integers have a median of 10. ("Distinct integers" means that no two integers are the same.)

What is the smallest the average of those ten integers could be?

Could you please explain your answer so i can understand how to go about this problem.

SmartMathMan  Dec 13, 2017
 #1
avatar+89889 
+2

If the median is 10, the fifth and sixth values must sum to 20, because in an even set of values, the median is the sum of the middle two values  divided by 2

 

We want   the sum of the first four digits and the last four  digits to be as small as possible

 

1,2,3,4    would work for the first four

 

If we let the fifth number be 5  the sixth would have to be 15  and the smallest that the remaining values could be is 16,17,18, 19.....but the average of this set  = 10

 

The minimum average is achieved when the two numbers that sum to 20 are odds that differ by 2, i.e., 9 and 11

 

So...the data set that produces the smallest average is

 

1,2,3,4,9,11,12,13,14,15   =   8.4

 

 

cool cool cool

CPhill  Dec 13, 2017

30 Online Users

avatar
avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.