A sequence is formed by adding $2$ to the triple of the previous term. If the first term is $1$, how many multiples of $6$ less than $10{,}000$ would be terms of the sequence?

Guest Dec 19, 2020

#1**0 **

A sequence is formed by adding 2 to the triple of the previous term. If the first term is 1 , how many multiples of 6 less than 10000 would be terms of the sequence?

Do you undestand the question?

First term = 1

2nd term =1 x 3 + 2 = 5

3rd term =5 x 3 + 2 = 17

4th term =17 x 3 + 2 = 53

5th term =53 x 3 + 2 = 161

6th term=161 x 3 + 2 = 485

7th term=485 x 3 + 2 = 1457

8th term=1457 x 3 + 2 =4373

9th term=4373 x 3 + 2 =Goes over 10,000

Of the 8 terms, how many of them are multiple of 6? Or are divisible by 6? Use your calculator and find out!.

Guest Dec 19, 2020