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# help plz

0
109
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+190

Find all nonnegative numbers x such that $$\sqrt{x}+2=\sqrt{x+100}.$$

Oct 16, 2019

#3
+2

Solve for x:
sqrt(x) + 2 = sqrt(x + 100)

Raise both sides to the power of 2:
(sqrt(x) + 2)^2 = x + 100

Subtract x + 100 from both sides:
-100 + (sqrt(x) + 2)^2 - x = 0

-100 + (sqrt(x) + 2)^2 - x = 4 sqrt(x) - 96:
4 sqrt(x) - 96 = 0

4 sqrt(x) = 96

Divide both sides by 4:
sqrt(x) = 24

Raise both sides to the power of two:

x = 576

Oct 16, 2019

#1
+2

I could find only one positive value for x:

x = 576

Oct 16, 2019
#2
+999
0

I graphed the equations and found that the only value is x = 576

Oct 16, 2019
#3
+2

Solve for x:
sqrt(x) + 2 = sqrt(x + 100)

Raise both sides to the power of 2:
(sqrt(x) + 2)^2 = x + 100

Subtract x + 100 from both sides:
-100 + (sqrt(x) + 2)^2 - x = 0

-100 + (sqrt(x) + 2)^2 - x = 4 sqrt(x) - 96:
4 sqrt(x) - 96 = 0

4 sqrt(x) = 96

Divide both sides by 4:
sqrt(x) = 24

Raise both sides to the power of two:

x = 576

Guest Oct 16, 2019