+0  
 
+1
906
3
avatar+220 

Find all nonnegative numbers x such that \(\sqrt{x}+2=\sqrt{x+100}.\)

 Oct 16, 2019

Best Answer 

 #3
avatar
+2

Solve for x:
sqrt(x) + 2 = sqrt(x + 100)

Raise both sides to the power of 2:
(sqrt(x) + 2)^2 = x + 100

Subtract x + 100 from both sides:
-100 + (sqrt(x) + 2)^2 - x = 0

-100 + (sqrt(x) + 2)^2 - x = 4 sqrt(x) - 96:
4 sqrt(x) - 96 = 0

Add 96 to both sides:
4 sqrt(x) = 96

Divide both sides by 4:
sqrt(x) = 24

Raise both sides to the power of two:
 
 x = 576

 Oct 16, 2019
 #1
avatar
+2

I could find only one positive value for x:

 

x = 576

 Oct 16, 2019
 #2
avatar+1252 
0

I graphed the equations and found that the only value is x = 576

 Oct 16, 2019
 #3
avatar
+2
Best Answer

Solve for x:
sqrt(x) + 2 = sqrt(x + 100)

Raise both sides to the power of 2:
(sqrt(x) + 2)^2 = x + 100

Subtract x + 100 from both sides:
-100 + (sqrt(x) + 2)^2 - x = 0

-100 + (sqrt(x) + 2)^2 - x = 4 sqrt(x) - 96:
4 sqrt(x) - 96 = 0

Add 96 to both sides:
4 sqrt(x) = 96

Divide both sides by 4:
sqrt(x) = 24

Raise both sides to the power of two:
 
 x = 576

Guest Oct 16, 2019

4 Online Users