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A 100-foot rope is cut into three pieces. The first piece is three times as long as the second, and the third piece is 30 feet shorter than the second. How many feet long is the shortest piece?

 Jul 18, 2021
 #1
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We can split it up by saying that:

 

\(100 = 3x + x + (x-30)\)

 

assuming we use the second piece as X since it's the only one both have comparisons to.

 

so:

 

\(100 = 3x+x+(x-30) 100=4x+(x-30) 100=4x+x-30 100=5x-30 130=5x 26=x\)

 

So, the final answer is \(\fbox{26}\) feet

 Jul 18, 2021
 #2
avatar+320 
+2

Hey there, Guest!

 

So, let's say that the second piece is length x.

 

The first piece is 3 times that, so it is 3x.

The 3rd piece is 20 feet shorter than it, so it is x-20.

 

Adding them, we get 5x-20, and that equals 100. 

Solving for x, we get 24.

So the lengths are 72, 24 and 4.

 

Hope this helped! :)

( ゚д゚)つ Bye

 Jul 18, 2021
 #3
avatar+63 
0

It's actually 30 feet shorter. Don't worry. Just a mere typo. cheeky 

PBJcatalinasandwich  Jul 19, 2021
edited by PBJcatalinasandwich  Jul 19, 2021

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