The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 30 feet in height?
We can set 30 equal to y, and we have the equation: \(30 = -6t^2 + 51t\)
Subtracting 30 from both sides, we get: \(0 = -6t^2 + 51t - 30\)
Now, we can use the quadratic formula: \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\), to get \({17 \pm \sqrt {209}} \over 4\).
But, we are looking for the first time it reaches 30 ft, so the answer is \(\color{brown}\boxed{{17 - \sqrt {209}} \over 4}\)
The \over function is used for fractions, so example, 1/2 is 1 \over 2
Curly brackets ({), are the equivalent of parenthesis in PEMDAS, so, for example, 1/2 = 0.5, would be {1 \over 2} = 0.5. The brackets around the fraction separate the fractions, without them, it would be \(1 \over 2 = 0.5\).
Next, the square root function is \sqrt{} (where the number is inside the bracket), so, \(\sqrt {209}\) is \sqrt{209}.
So, \({17 - \sqrt {209}} \over 4\) is {17 - \sqrt{209}} \over 4.
To box something, use the \boxed{} function, where the thing that is being boxed goes inside the curly brackets.
To make it a different color, use the /color{insert color here}{}, where the color goes in the first pair of brackets and the thing that you would like to change he color of.
Putting all these concepts together, \(\color{brown}\boxed{17 - \sqrt {209} \over 4}\) in raw form is "\color{brown}\boxed{17 - \sqrt {209} \over 4}".
/color{brown} makes everything brown, /boxed boxes the entire thing in brown, and the brackets immediately after that define the fraction that is being boxed. The \sqrt{209} makes the square root of 209, and \over 4 makes a fraction with a denominator of 4 and a numerator with everything before it ( in this case 17 - \sqrt {209}).
More info available here: https://web2.0calc.com/questions/latex-coding
Also, sorry if this isn't helpful, I'm not the best at explaining...