The area of the trapezoid ABCD is equal to 60. The length of one of of the bases is 9 units greater than the other base, and the height of trapezoid ABCD is equal to 8. What is the legth of the median of trapezoid ABCD
+238 To find the bases, we can plug in our known values with x being the smaller base,
\(\frac{2x+9}{2}\cdot 8 = 60\)
\(\frac{2x+9}{2}=7.5\)
\(2x+9 = 15\)
\(x = 3\)
The smaller base is 3, and the larger is 12. The median of a trapezoid is just the average of the bases. So (3+12)/2 = 7.5 which is our answer.
