help plz

The area of the base is 6 x 6 = 36.

Since the left-hand triangle of the front side is a 45-45-90 triangle, the length of the dotted line segment (the height) of the front triangle is equal to the distance from the left-hand corner dot to the middle dot of the front side.

Because the length of the base of the front side is 6, the distance from the left-hand corner dot to the middle dot is 3; therefore, the length of the height of the front side is also 3.

The area of the front side is 1/2 x base x height = 1/2 x 6 x 3  =  9.

The total area = (area of the base) + 4 x (area of the front side)  =  (36) + 4 x (9)  =  72 square feet.

$\text{Slant height}=\dfrac{\frac{6}{2}}{\sin45^{\circ}}=3\sqrt2\\ \text{Surface area} = 6^2 + 4\times \dfrac{1}{2}\times 6\times 3\sqrt2\times \sin45^{\circ}\\ \qquad\qquad\;\;\;\;\;\!\;\;\!\!=36 + 36 \\\qquad\qquad\;\;\;\;\;\!\;\;\!\!=72$

Area of any triangle: a and b are 2 side lengths of the triangle and C is the included angle of a and b, then area = $\dfrac{ab\sin C}{2}$.