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# Help plz

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The Oddville Academy offers three languages: Oriya, Dakhini, and Dutch (how odd!). Each student takes an odd number of languages – that is, every student takes either one language or three languages.

Let x be the number of students taking Oriya, y be the number of students taking Dakhini, z be the number of students taking Dutch, and t be the number of students taking all three languages. Find an expression in terms of x, y, z, and t for the total number of students at the Oddville Academy.

Guest Jun 2, 2017

#2
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You are very observant about those first letters ZZZ...  but your logic is just a little off :))

There are t students taking all three and the rest take only 1 language so

The number taking only Oriya is x-t

The number taking only Dakhini is y-t

The number taking only Dutch is z-t

So the number of students altogether is

x-t  +  y-t  +  z-t  +  t   = x+y+z-2t

Melody  Jun 2, 2017
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x+y+z+t=number of students at Oddville Academy

(Also I noticed that the languages' first letters spell "odd")

ZZZZZZ  Jun 2, 2017
#2
+94118
+2

You are very observant about those first letters ZZZ...  but your logic is just a little off :))

There are t students taking all three and the rest take only 1 language so

The number taking only Oriya is x-t

The number taking only Dakhini is y-t

The number taking only Dutch is z-t

So the number of students altogether is

x-t  +  y-t  +  z-t  +  t   = x+y+z-2t

Melody  Jun 2, 2017