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For what real values of c$ is $x^2 + 16x + c$ the square of a binomial? If you find more than one, then list your values separated by commas.

 

(Its not  (16/2)^2 . or  x^2+16x+64

 May 23, 2019
edited by samus  May 23, 2019
 #1
avatar+111438 
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x^2 + 16x +c

 

If this is a square of a binomial..we only have one real solution...so...the discriminant must = 0.....therefore

 

16^2  - 4(1)c = 0

 

256  =  4c

 

64  =  c

 

The binomial  is (x + 8)^2

 

cool cool cool

 May 23, 2019
edited by CPhill  May 23, 2019

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