For what real values of c$ is $x^2 + 16x + c$ the square of a binomial? If you find more than one, then list your values separated by commas.
(Its not (16/2)^2 . or x^2+16x+64
x^2 + 16x +c
If this is a square of a binomial..we only have one real solution...so...the discriminant must = 0.....therefore
16^2 - 4(1)c = 0
256 = 4c
64 = c
The binomial is (x + 8)^2
