Help plz

Sum of cubes => a^3 + b^3 = (a + b)(a^2 - ab + b^2)

a^2 - ab + b^2 = (a + b)^2 - 2ab - ab

a^3 + b^3 = 14((14)^2 - 3ab)

812/14 = 196 - 3ab

58 - 196 = -3ab

ab = 46

a + b = 14.

By vieta's formula, we can write a quadratic: x^2 - 14x + 46 = 0, where a and b are the solutions to the quadratic.

[14 +- sqrt(196 - 184)]/2

(14 +- sqrt(12))/2

(14 +- 2sqrt(3))/2

7 +- sqrt(3).

Thus (a, b) = $(7 + \sqrt{3}, 7 - \sqrt{3})$ and you can reverse a and b in the ordered pair.