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# HELP PLZZZZZ

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50
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+189

$$(-2)^4 - 2^4 + (-3)^3 - 3^3$$

I was wondering how to attack this problem

May 3, 2020

#1
+656
+1

Ok here's my solution,

\begin{align*} (-2)^4 &= (-2)(-2)(-2)(-2) = 16,\\ 2^4 &= 2\cdot 2\cdot 2\cdot 2 = 16,\\ (-3)^3&= (-3)(-3)(-3) = (9)(-3) = -27,\\ 3^3 &= 3\cdot3\cdot3 = 27, \end{align*}

$$(-2)^4 -2^4 + (-3)^3 - 3^3 = 16-16 -27-27 = \boxed{-54}.]$$

So the thing to take away in this question is to always remember that in solving these questions the order of operations in KEY!!!

May 3, 2020

#1
+656
+1

Ok here's my solution,

\begin{align*} (-2)^4 &= (-2)(-2)(-2)(-2) = 16,\\ 2^4 &= 2\cdot 2\cdot 2\cdot 2 = 16,\\ (-3)^3&= (-3)(-3)(-3) = (9)(-3) = -27,\\ 3^3 &= 3\cdot3\cdot3 = 27, \end{align*}

$$(-2)^4 -2^4 + (-3)^3 - 3^3 = 16-16 -27-27 = \boxed{-54}.]$$

So the thing to take away in this question is to always remember that in solving these questions the order of operations in KEY!!!

LuckyDucky May 3, 2020
#3
+189
+1

Thanks, Ducky! but what about factorials and brackets how do they fit in?

SoggyPerson  May 3, 2020
#4
+111360
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Excellent, LD!!!!!!

CPhill  May 3, 2020
#5
+656
+2

This image is excellent I recommend to view it!

LuckyDucky  May 3, 2020
#6
+189
+2

Thx!

SoggyPerson  May 3, 2020
#2
+1

-2= 16

- 2^4 =  - 16

-3^3 = -27

-3^3 =  - 27

May 3, 2020
#7
+51
0

That's an Art of Problem Solving question from Intro to Algebra... I took that...