A Senate committee consists of 5 Republicans, 6 Democrats, and 2 Independents. A subcommittee of 3 members is randomly chosen. What is the probability that the subcommittee consists of 1 Republican and 2 Democrats?
+9 A Senate committee consists of 5 Republicans, 6 Democrats, and 2 Independents. A subcommittee of 3 members is randomly chosen. What is the probability that the subcommittee consists of 1 Republican and 2 Democrats?
Out of 5+6+2=13 total members we must choose a 3 member subcommittee. There is \(\binom{13}{3}=286\) ways to do this. There are 5 ways to choose the Republican and \(6\cdot5=30\) ways to choose the Democrats. So, the probability is \(\frac{35}{286}\).
Please correct me if I'm wrong, I'm not the best at committee problems.
+118687 Nice try Supernova :)
But you messed up a bit on the numerator.
It is multiply not plus.
Becasue.. for EVERY pair of democrats, there are 5 choices of republican - hence multiply.
also
Choosing R1 then R2 is the same as choosing R2 then R1 so you would have to halve that part of your answer.
Alternatively, you could say there are 6C2 ways to chose the democrats and 5 ways to chose the republican so the numerator would be
6C2*5 = 15*5 = 75
