kx^2 - 70x + 2k = 0
Find the maximum integral value of k for which the above quadratic equation has two distinct real roots.
+33615 "kx^2 - 70x + 2k = 0
Find the maximum integral value of k for which the above quadratic equation has two distinct real roots."
First find the value of k that gives exactly one root, then take the nearest integer saller than that.
To find the value of k that gives exactly one root, set the discriminant to zero. In this case that is:
70^2 - 4*k*2*k = 0
I'll leave you to solve for k etc.
