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kx^2 - 70x + 2k = 0

 

Find the maximum integral value of k for which the above quadratic equation has two distinct real roots.

 Jul 2, 2021
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"kx^2 - 70x + 2k = 0

Find the maximum integral value of k for which the above quadratic equation has two distinct real roots."

 

First find the value of k that gives exactly one root, then take the nearest integer saller than that.

 

To find the value of k that gives exactly one root, set the discriminant to zero.  In this case that is:

 

70^2 - 4*k*2*k = 0

 

I'll leave you to solve for k etc.

 Jul 2, 2021

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