The height (in meters) of a shot cannonball follows a trajectory given by h(t) = -4.9t^2 + 14t - 0.4 at time t (in seconds). As an improper fraction, for how long is the cannonball above a height of 8.7 meters?
+37146 Use 8.7 as h
8.7 = -4.9t^2 + 14t - 0.4 re-arrange to:
-4.9t^2 + 14t - 9.1 Now use Quadratic Formula to find the solution values of 't' subtract the smaller from the larger for your answer
a = -4.9 b = 14 c = -9.1
\(t = {-14 \pm \sqrt{14^2-4(-4.9)(-9.1)} \over 2(-4.9)}\)
+37146 Use 8.7 as h
8.7 = -4.9t^2 + 14t - 0.4 re-arrange to:
-4.9t^2 + 14t - 9.1 Now use Quadratic Formula to find the solution values of 't' subtract the smaller from the larger for your answer
a = -4.9 b = 14 c = -9.1
\(t = {-14 \pm \sqrt{14^2-4(-4.9)(-9.1)} \over 2(-4.9)}\)
