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By joining alternate vertices of a regular hexagon with edges  inches long, two equilateral triangles are formed, as shown. What is the area, in square inches, of the region that is common to the two triangles? Express your answer in simplest radical form.

Any help would be greatly appreciated. Thank you.

 Aug 24, 2020
 #1
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The area that the two triangles have in common is 8*sqrt(3).

 Aug 24, 2020
 #2
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I dont know why my image is blocked by the mod. can you see it?

 Aug 24, 2020
 #3
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Thank you! tHat was a good answer. Can you explain how you got that though? It is correct.

 Aug 24, 2020

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