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Factor (x^2+y^2-z^2)^2-4x^2y^2as the product of four polynomials of degree 1. 

 Feb 27, 2018

Best Answer 

 #1
avatar+2446 
+1

I have found a way to factor the original expression (x2+y2z2)24x2y2.

 

(x2+y2z2)24x2y2(x2+y2z2)2(2xy)2 Although this may not be immediately obvious, the original expression is a difference of squares. I rewrote the original expression to make this fact clearer. Remember thata2b2=(a+b)(ab). Factor the expression as such. I have used colors to make this process easier for your eyes to digest.
(x2+y2z2+2xy)(x2+y2z22xy) Let's do some rearranging here. 
(x2+2xy+y2z2)(x22xy+y2z2) Why am I highlighting this part? Well, both portions happened to be perfect-square trinomials. 
([x+y]2z2)([xy]2z2) Do you notice something? Yes, it is another difference of squares. It is time to factor again!
([x+y]2z2)=(x+y+z)(x+yz)([xy]2z2)=(xy+z)(xyz) I have factored each one individually. The last step is to combine the factors into one expression.
(x+y+z)(x+yz)(xy+z)(xyz) This expression satisfies the original condition; the final expression is "the product of four polynomials of degree 1."
   
 Feb 27, 2018
 #1
avatar+2446 
+1
Best Answer

I have found a way to factor the original expression (x2+y2z2)24x2y2.

 

(x2+y2z2)24x2y2(x2+y2z2)2(2xy)2 Although this may not be immediately obvious, the original expression is a difference of squares. I rewrote the original expression to make this fact clearer. Remember thata2b2=(a+b)(ab). Factor the expression as such. I have used colors to make this process easier for your eyes to digest.
(x2+y2z2+2xy)(x2+y2z22xy) Let's do some rearranging here. 
(x2+2xy+y2z2)(x22xy+y2z2) Why am I highlighting this part? Well, both portions happened to be perfect-square trinomials. 
([x+y]2z2)([xy]2z2) Do you notice something? Yes, it is another difference of squares. It is time to factor again!
([x+y]2z2)=(x+y+z)(x+yz)([xy]2z2)=(xy+z)(xyz) I have factored each one individually. The last step is to combine the factors into one expression.
(x+y+z)(x+yz)(xy+z)(xyz) This expression satisfies the original condition; the final expression is "the product of four polynomials of degree 1."
   
TheXSquaredFactor Feb 27, 2018

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