Find the number of ways of arranging the numbers 1, 2, 3, 9 in a circle, so that the sum of any three adjacent numbers is divisible by 3. (Two arrangements are considered the same if one arrangement can be rotated to obtain the other.)
Find the number of ways of arranging the numbers 1, 2, 3, 9 in a circle, so that the sum of any three adjacent numbers is divisible by 3. (Two arrangements are considered the same if one arrangement can be rotated to obtain the other.)
There are none.
No the numbers in the question are 1,2,3 and 9
No other numbers are mentioned.
There are no possible combinations
Sorry. It seems like I made a typo in the question. The correct question is: Find the number of ways of arranging the numbers 1, 2, 3,... 9 in a circle, so that the sum of any three adjacent numbers is divisible by 3. (Two arrangements are considered the same if one arrangement can be rotated to obtain the other.)