f(x) = 5(x - 1/2)^2 (x-1)^2 + 5
for the above defined function f, what is the solution set of the equation f(x) = 5?
For f(x) to equal 5 the term 5(x - 1/2)^2 (x-1)^2 must be zero. Look carefully at this term. What two values of x will make it zero?
i thought they wanted me to set it euqal to each other like 5 = 5(x - 1/2)^2 (x-1)^2 + 5
then multiply it out the right side but i cant manage to do that. when plugging it into a calculator i get different multiplication than waht i did and they want me to pay to show the steps on how they were able to figure it out. The answers were 1 and .5 but i am unable to get these results.