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avatar+206 

f(x) = 5(x - 1/2)^2  (x-1)^2 + 5

for the above defined function f, what is the solution set of the equation f(x) = 5?

 Aug 22, 2020
 #1
avatar+30915 
+2

For f(x) to equal 5 the term 5(x - 1/2)^2  (x-1)^2 must be zero.  Look carefully at this term.  What two values of x will make it zero?

 Aug 22, 2020
 #2
avatar+206 
+1

i thought they wanted me to set it euqal to each other like 5 = 5(x - 1/2)^2  (x-1)^2 + 5

then multiply it out the right side but i cant manage to do that. when plugging it into a calculator i get different multiplication than waht i did and they want me to pay to show the steps on how they were able to figure it out. The answers were 1 and .5 but i am unable to get these results.

BLANK  Aug 22, 2020
 #3
avatar+30915 
+2

Just look at the term 5(x - 1/2)^2  (x-1)^2   

 

What happens to this term if you plug in x = 1/2?

 

What happens to it if you plug in x = 1?

 Aug 22, 2020

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