How many times is the sum of two fractions bigger than their difference, if one of the fractions is \(138\frac{6}{13}\) percent of the other?
138 + 6/13 % = (1800 / 13) % = (1800/13) / 100 = 1800 /1300 = 18/13
Call the smaller fraction F and the larger one (18/13)F
Sum = F + (18/13)F = (31/13)F
Difference = (18/13)F - F = (5/13) F
Ratio of sum / difference = (31/13) F / [ (5/13) F ] = 31/5 = 6 and 1/5 times
+479 
