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How many times is the sum of two fractions bigger than their difference, if one of the fractions is \(138\frac{6}{13}\) percent of the other?

 Dec 3, 2020
 #1
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138 + 6/13  % =      (1800 / 13) %  =  (1800/13)  / 100  =   1800 /1300  =  18/13

 

Call  the smaller fraction  F     and the larger   one  (18/13)F

 

Sum  =   F + (18/13)F  =  (31/13)F

Difference  =  (18/13)F  - F  =  (5/13) F

 

Ratio  of  sum  / difference  =   (31/13) F /  [  (5/13) F ]  =    31/5  =   6 and 1/5 times

 

 

cool cool cool

 Dec 3, 2020

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