Solve for \(x\): \(\frac{3x - 1}{4x-4} = \frac23.\)
Should I simplify it, or...?
(I'm a new user so I don't know if I'm doing this correctly)
Welcome ChocoSwirl.
(3x-1)/(4x-4) = 2/3
The first thing I want to do is to get rid of the denominator, I can do this my multiplying 3(4x-4) on both sides. Note than x can't be 1 since 4(1) - 4 = 0, and zero can't be a denominator.
(3x-1)3 = 2(4x - 4)
Next, I'm going to expand.
9x - 3 = 8x - 8
Going to subtract 8x from both sides.
x - 3 = -8
And finally, I'm going to add 3 to both sides.
x = -5
I hope that made sense. :))
=^._>^=