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1. The vertex of a parabola is at $(12, -4)$, and its axis of symmetry is vertical. One of the $x$-intercepts is at $(15, 0)$. What is the $x$-coordinate of the other $x$-intercept?

 

2. The $x$-intercepts of the parabola $y = x^2 + bx + c$ are $(-3,0)$ and $(5,0).$ Find the equation of the parabola, and submit your answer in $y = ax^2 + bx + c$ form.

 Feb 1, 2021
 #1
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The other x intercept will be the same distance from the vertex axis of symmetry as the one given...but on THE OTHER SIDE

9,0

 Feb 1, 2021
 #2
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Guest the answer is 0, 9 not 9, 0.

 Feb 1, 2021

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