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Stall A sold watermelons at $4 each and Stall B sold pineapples at

$2.50 each. The number of watermelons in Stall A was 3/4 as many as the

number of pineapples in Stall B. When Stall A sold 52 watermelons, Stall B

gave Stall A the same number of pineapples to sell. The ratio of the number

of pineapples in Stall B to the number of fruits in Stall A now is 7:15.

Find the total cost of the watermelons and pineapples at first.

 Feb 12, 2022
edited by Guest  Feb 12, 2022
 #1
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Call the number of pineapples originally in Stall B =  P

Call the number of watermelons originally in Stall A = W

And we  know that   (3/4)P =  W  

When Stall A  sells  52 watermelons and gets 52 pineapples from Stall B, it  still contains

W fruits =  (3/4)P

And, at the end, Stall B contains P -52   pineapples

 

And the  ratio  of the  number of pineapples in Stall B to number of fruits in Stall A =  7/15

 

So

 

P - 52               7

_____  =       ____           cross-multiply

(3/4)P              15

 

15 (P -52) = 7(3/4)P

 

15P - 780 =  (21/4)P

 

15P - (21/4)P  = 780

 

(60 - 21) / 4  * P = 780

 

39 / 4  * P  = 780

 

P  =  780 * (4/39)    =   20 * 4  =   80  pineapples in Stall B at first

 

(3/4) P  = (3/4) * 80  =   60  watermelons in Stall A at first  

 

Total cost of all the fruits at first  = 60 ( $4)  + 80 ($2.50)  =  $240 + $200  =  $440

 

cool cool cool

 Apr 2, 2022

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