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In triangle ABC, CA=4sqrt(2), CB=4sqrt(3), and A= \(45\) degrees. What is B in degrees?

 Apr 19, 2022
 #1
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Applying the Law of Sines yields:

\(\dfrac{CA}{\sin B} = \dfrac{CB}{\sin A}\)

 

After some simplification, 

\(\sin B = \dfrac{CA \cdot \sin A}{CB} = \dfrac{4 \sqrt 2 \sin 45^\circ}{4\sqrt 3}\)

 

Now you can find the value of sin B, and hence the value of B using inverse trigonometric function.

 Apr 19, 2022

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