+9673 If the odd function is continuous, it must pass through (0,0) as the property of odd function is that the graph of the function is rotational symmetrical about the origin.
Substitute (2,-2) into g(x) = f(x+3) - 5.
\(-2 = f(5) - 5\\ f(5) = 3\)
From this, we get \(f(-5) = -3\).
When x = -8,
\(g(-8) = f(-5) - 5\\ g(-8) = -3-5 = -8\).
So it must also pass through (-8,-8).
Answer: (0,0), (-8,-8)
