In how many ways can 4 balls be placed in 3 boxes if the balls are indistinguishable, and the boxes are distinguishable?
Answer is not 37
There are 3 boxes, so there are 3 ways to place the first ball. There are 2 boxes left, so there are 2 ways to place the second ball. There is 1 box left, so there is 1 way to place the third ball. There is 1 box left, so there is 1 way to place the fourth ball. Therefore, there are 3 * 2 * 1 * 1 = 6 ways to place the 4 balls in 3 boxes.