F(x) = \(f'(x)= {x^5-5x^4+x \over x^3}\)
I know I have to use u'v*uv' / v^2
In this case my u = x^5-5x^4+x v= x^3
u' = 5x^4-20x^3 +1 v'= 3x^2
but I don't seem to get the correct answer. Could anyone please help me understand how to get to the correct answer which is 2x-5 -2/x^3
I don't particularly like using the quotient rule, but here goes
[ (5x^4-20x^3 +1)(x^3) - ( x^5-5x^4+x )(3x^2)] / x^6
[ 5x^7 - 20x^6 + x^3 - 3x^7 + 15x^6 - 3x^3] / x^6
[2x^7 - 5x^6 -2x^3] / x^6 =
[2x^7]/ x^6 - [5x^6]/x^6 - [2x^3]/ x^6
2x - 5 - 2 / x^3
And there you are.....!!!!
I don't particularly like using the quotient rule, but here goes
[ (5x^4-20x^3 +1)(x^3) - ( x^5-5x^4+x )(3x^2)] / x^6
[ 5x^7 - 20x^6 + x^3 - 3x^7 + 15x^6 - 3x^3] / x^6
[2x^7 - 5x^6 -2x^3] / x^6 =
[2x^7]/ x^6 - [5x^6]/x^6 - [2x^3]/ x^6
2x - 5 - 2 / x^3
And there you are.....!!!!