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Post one question and learn from the answer.

Then if you need to post another afterwards.

 Mar 8, 2019
edited by Melody  Mar 8, 2019
 #1
avatar+106080 
+2

the parent sin funtion is 

\(y=sin \theta\)

this has a amplitude of 1, a period of 2pi (radians) , the wave centre is the line y=0  (the theta axis)   and no phase shift.

 

\(y=sin (n\theta) \)

This has a period of     2pi/n    nothing else has changed

 

\(y=a\cdot sin \theta\)

This has an amplitude of a           Everything else is the same as the parent function.

 

\(y=sin \theta+L\)

Lifts the parent funtion by L units.

 

Now what would be a good starting point do you think for this graph. It may need tweaking afterwards?

 

Now graph your function with desmos.  Use x instead of theta, I do not think theta will work.

Ive started you off with the parent funtions. You add what you think is write underneath and see if it works.

https://www.desmos.com/calculator/ml97kwixwz

 

If you interact with me I will be very impressed.

 

 

Please no one answer over the top of me.  I am attempting to help our guest learn.

 Mar 8, 2019
 #2
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+1

https://www.desmos.com/calculator/exp2ewjoza

 

Am I doing this right? Also, I appreciate you. 

 Mar 8, 2019
edited by Guest  Mar 8, 2019
 #3
avatar+106080 
+1

Yes that looks really good to me.    Nice work!   

And thanks for your gratitude, I appreciate it  laugh

 

Did they want you to graph it like this or did they want you to do it with points?  Do you know?

 

 

I modified your graph just a little bit. I used the spanner tool in the top right corner to sset the units to 1,2,3 etc instead of  pi

 

And on the second graph y=1 I made it so it could not be moved by saying it had to be from 1 to 1. 

If you look at my graph you will see what I mean.

 

https://www.desmos.com/calculator/hi0xoy1eps

Desmos is a wonderful grahing tool. It will be worth your while to learn to use it very well.

Melody  Mar 8, 2019
edited by Melody  Mar 8, 2019
edited by Melody  Mar 8, 2019
 #4
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+1

I just need a point at the midline and a point at the maximum or minimum closest to the first point. Thanks again.

Guest Mar 8, 2019
 #5
avatar+106080 
0

I'll try and show you how to graph it by hand.  I will be back in a little while :)

Melody  Mar 8, 2019
 #6
avatar+106080 
+1

Ok here it is without knowing the formula at all.

I think my hand sketching needs practice though  LOL

 

Melody  Mar 8, 2019
 #7
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+1

Looks good smiley I appreciate all the effort you put into helping me. 

Guest Mar 8, 2019

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