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Our basketball team has 10 players, including Steve and Danny. We need to divide into two teams of 5 for an intra-squad scrimmage. In how many ways can we do this if Steve and Danny insist on playing on the same team?

 

I tried 8 choose 3 to pick the remaing 3 players that play with Steve and Danny. I then multiply by 2 because we have 2 teams, but I am not sure if this is correct. I got 112, please explain your answer. 

 Dec 15, 2022
 #2
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The number of ways is C(10,5)

 Dec 18, 2022
 #3
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Thanks!

Guest Dec 18, 2022

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