+0  
 
0
126
3
avatar

Our basketball team has 10 players, including Steve and Danny. We need to divide into two teams of 5 for an intra-squad scrimmage. In how many ways can we do this if Steve and Danny insist on playing on the same team?

 

I tried 8 choose 3 to pick the remaing 3 players that play with Steve and Danny. I then multiply by 2 because we have 2 teams, but I am not sure if this is correct. I got 112, please explain your answer. 

 Dec 15, 2022
 #2
avatar
0

The number of ways is C(10,5)

 Dec 18, 2022
 #3
avatar
0

Thanks!

Guest Dec 18, 2022

0 Online Users