+0  
 
0
3
1
avatar+1479 

A speech class has $4$ freshmen and $3$ sophomores. (Everyone is distinguishable.) In how many ways can they stand in line, so that all the sophomores are standing together?

 Dec 29, 2023
 #1
avatar+126665 
+1

The sophomores can occupy  any one of 5 positions

For each of these they can  be  arranged in 3! = 6 ways

And for each of these the  freshmen can be  arranged in 4! = 24 ways

 

So

5 * 6 * 24  =   720 arrangements

 

 

 

cool cool cool

 Dec 29, 2023
edited by CPhill  Dec 29, 2023

3 Online Users

avatar