Find all real solutions for \(x\) in \(2(2^x- 1) x^2 + (2^{x^2}-2)x = 2^{x+1} -2 .\)
I found x = -1, 0, and x = 1 as solutions to this problem, but how do I prove these are the only solutions?
Isn't it a 3rd order equation because of: 2^x^2 term? if that is the case, then there are only the 3 solutions you found.
How does the 2^(x^2) term mean that the equation is 3rd order?