+0  
 
0
97
1
avatar

For real numbers x, let

f(x) = x + 2 if x > 3,

f(x) = 2x^2 + 3x + a if x <= 3.

 

What must the value of a be to make the piecewise function continuous (which means that its graph can be drawn without lifting your pencil from the paper)?

 Jun 20, 2021
 #1
avatar+32668 
+1

The two expressions must be equal when x = 3, so:

 

3 + 2 = 2*3^2 + 3*3 + a

so

5 = 27 + a

 

I'll leave you to find a from this.

 Jun 20, 2021

32 Online Users