Andrew draws this figure in the sand with his nose. The sum of the areas of the shaded regions can be represented with the expression a*pi + b, where a and b are nonnegative integers. Find a + b.
The Area of the bottom-most rectangle is 60 * 20 = 800 u2.
The Area of the "ring" is simply the difference of the two circles with the inner and outer radii.
Inner radius = 50 - 20 = 30u
Outer radius = 50u
Area = πrouter2 - 30πrinner2
Area = π502 - π302
Area = 2500π - 900π
Area = 1600π u2
The Area of the "V" in the center can be simply divided up into two congruent parallelograms and a trapezoid.
Areaparrellogram= bh = 30*10 = 300 u2
Since we have 2 of these, the total is 300*2 = 600 u2
Areatrapezoid= h(a+b)/2 = 15(10+20)/2 = 15*30/2 = 225 u2
Area"V"= 600 + 225 = 825 u2
Now the total area is the sum of the areas of the "V", the ring, and the rectangle. (Sum of everything underlined)
825 + 1600π + 800 = 1600π + 1625 u2
From above, we can deduce that a = 1600, and b = 1625.
Therefore a+b = 3225 u2.