#1**+2 **

**Triangle \(ABC\) is acute. Point \(D\) lies on \(\overline {AC}\) so that \(\overline {BD}\perp \overline {AC}\), and point \(E\) lies on \(\overline {AB}\) such that \(\overline {CE}\perp\overline {AB}\). The intersection of segments \(\overline {CE}\) and \(\overline {BD} \)is \(P\). Find the value of \(\overline{AE}\) if \(\overline{CP}=10\), \(\overline{PE}=20\), and \(\overline{EB}=30\).**

answer see: https://web2.0calc.com/questions/help_94586#r2

heureka Sep 23, 2019