Help With Geometry!

Triangle $ABC$ is acute. Point $D$ lies on $\overline {AC}$ so that $\overline {BD}\perp \overline {AC}$,
and point $E$ lies on $\overline {AB}$ such that $\overline {CE}\perp\overline {AB}$.
The intersection of segments $\overline {CE}$ and $\overline {BD}$is $P$.
Find the value of $\overline{AE}$ if $\overline{CP}=10$, $\overline{PE}=20$, and $\overline{EB}=30$.

answer see: https://web2.0calc.com/questions/help_94586#r2