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Thanks!

 Sep 22, 2019
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Triangle \(ABC\) is acute. Point \(D\) lies on \(\overline {AC}\) so that \(\overline {BD}\perp \overline {AC}\),
and point \(E\) lies on \(\overline {AB}\) such that \(\overline {CE}\perp\overline {AB}\).
The intersection of segments \(\overline {CE}\) and \(\overline {BD} \)is \(P\).
Find the value of \(\overline{AE}\) if \(\overline{CP}=10\), \(\overline{PE}=20\), and \(\overline{EB}=30\).

 

answer see: https://web2.0calc.com/questions/help_94586#r2

 

 

laugh

 Sep 23, 2019

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