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Suppose that we have a right triangle  ABC with the right angle at  B such that AC=√(61) and AB=5. A circle is drawn with its center on AB such that the circle is tangent to AC and BC. If P is the point where the circle and side AC meet, then what is CP?

 Oct 8, 2020
 #1
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CP = 7.

 Oct 9, 2020
 #2
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CP = BC = sqrt( 61 - 52) = 6

 Oct 9, 2020

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