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PQRS is a rhombus with perimeter = 28 units and PR = 8 units, find b (QT)

 

 Feb 5, 2021

Best Answer 

 #2
avatar+73 
+3

28/4 = 7, which is one of the rhombus's sides. since we know PR is 8, PT would be 4, so now we can use Pythagorean Theorem to solve for QT.

 

7^2 = b^2+4^2

49 = b^2+16

33 = b^2

b = \(\sqrt33\)

 

 

i hope this helped! please correct me if i am wrong:)

 Feb 5, 2021
 #1
avatar+128 
+2

Wouldnt the answer be 4 units? Because PR is 8 and QT is half of PR. Someone correct me if im wrong.

 Feb 5, 2021
 #3
avatar+273 
+7

I agree, I also think it should be 4. ūü§Ē

IhaveOBJD  Feb 5, 2021
 #4
avatar+73 
+2

hmm, i am not sure... the diagonals of a rhombus do not necessarily have to be equal...

macar0ni  Feb 5, 2021
 #5
avatar+273 
+7

True that

IhaveOBJD  Feb 5, 2021
 #2
avatar+73 
+3
Best Answer

28/4 = 7, which is one of the rhombus's sides. since we know PR is 8, PT would be 4, so now we can use Pythagorean Theorem to solve for QT.

 

7^2 = b^2+4^2

49 = b^2+16

33 = b^2

b = \(\sqrt33\)

 

 

i hope this helped! please correct me if i am wrong:)

macar0ni Feb 5, 2021

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